Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders” are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic” collision?
B) Calculate the velocity of the glider combination immediately after the collision.
6 marks
3 answers
please help with B
is it 0.5 * 0.2= 0.11
then 0.11=1/0.55*0.20^2 though i dont think that makes much sense
then 0.11=1/0.55*0.20^2 though i dont think that makes much sense
Conservation of kinetic Energy.
0.5*M2*V^2 = 0.5*M1*V^2 + 0.5*M2*V^2.
0.5*0.25*0.2^2 = 0.5*0.3V^2+0.5*0.25V^2
0.005 = 0.15V^2 + 0.125V^2,
=.005 = 0.275V^2,
V^2 = 0.0182,
V = 0.135 m/s.
0.5*M2*V^2 = 0.5*M1*V^2 + 0.5*M2*V^2.
0.5*0.25*0.2^2 = 0.5*0.3V^2+0.5*0.25V^2
0.005 = 0.15V^2 + 0.125V^2,
=.005 = 0.275V^2,
V^2 = 0.0182,
V = 0.135 m/s.