To analyze the equation:
\[ 21H + 21H \rightarrow 42H + \text{energy} \]
In this reaction, we can break down the components:
- The notation \( 21H \) indicates hydrogen isotopes, specifically deuterium (\( ^2H \)), which has a mass number of 2.
- When two deuterium atoms combine, the product is \( 42H \), which indicates a heavier hydrogen isotope (\( ^4H \)) and has a mass number of 4.
So, in this reaction:
- The left side (reactants) has two atoms of \( ^2H \) (deuterium), each with a mass number of 2.
- The right side (products) has one atom of \( ^4H \) (a hydrogen isotope), with a mass number of 4.
Given this analysis, the best description of the mass numbers of the atoms in the reaction is:
There are two atoms with mass numbers of 2.