To analyze the equation:
\[ 21H + 21H \rightarrow 42H + \text{energy} \]
The notation \( 21H \) refers to hydrogen with a mass number of 2 (which indicates it is deuterium, an isotope of hydrogen). Thus, each \( 21H \) has a mass number of 2.
When two \( 21H \) (deuterium) atoms combine, they produce one \( 42H \) (which indicates a mass number of 4, as it represents an isotope of hydrogen called tritium).
Now let's evaluate the statements:
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There is one atom with a mass number of 1. - Incorrect, there are no mass numbers of 1 in this equation.
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There is one atom with a mass number of 2. - Incorrect, there are two atoms with a mass number of 2 before the reaction occurs, but none after.
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There are two atoms with mass numbers of 1. - Incorrect, as there are no mass numbers of 1 in this equation.
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There are two atoms with mass numbers of 2. - Correct, as you have two \( 21H \) atoms (each with mass number 2) before the reaction.
Based on the equation, the best choice is:
There are two atoms with mass numbers of 2.