Question

Use the equation of motion to answer the question.

x=x0+v0t+12at2


An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?

(1 point)
Responses

9 m
9 m

5.5 m
5.5 m

18 m
18 m

11 m
11 m
Skip to navigation

Answer 1

Given that the object has a starting position (\(x_0\)) of 2 m, a starting velocity (\(v_0\)) of 4.5 m/s, and no acceleration (\(a = 0\)), we can use the equation of motion:

\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]

In this case, since there is no acceleration, the equation simplifies to:

\[ x = x_0 + v_0 t \]

Now substituting the values:

- \(x_0 = 2 \, \text{m}\)
- \(v_0 = 4.5 \, \text{m/s}\)
- \(t = 2 \, \text{s}\)
- \(a = 0\)

Now calculate the final position:

\[ x = 2 \, \text{m} + (4.5 \, \text{m/s} \times 2 \, \text{s}) \]
\[ x = 2 \, \text{m} + 9 \, \text{m} \]
\[ x = 11 \, \text{m} \]

So the final position of the object after 2 seconds is **11 m**.