To find the final position of the object after 1 second, we can use the equation for motion given:
\[ x = x_0 + v_0t + \frac{1}{2}at^2 \]
In this case:
- \( x_0 = 2 \) m (initial position)
- \( v_0 = 15 \) m/s (initial velocity)
- \( a = 0 \) m/s² (since it's moving at a constant speed, the acceleration is zero)
- \( t = 1 \) s (time)
Substituting these values into the equation, we get:
\[ x = 2 + (15)(1) + \frac{1}{2}(0)(1^2) \]
This simplifies to:
\[ x = 2 + 15 + 0 \] \[ x = 17 \text{ m} \]
Hence, the final position of the object after 1 second is 17 m.