To determine the number of real solutions for the quadratic equation \( 4x^2 + 3x - 7 = 0 \), we will calculate the discriminant. The formula for the discriminant \( D \) of a quadratic equation \( ax^2 + bx + c = 0 \) is:
\[ D = b^2 - 4ac \]
Here, the coefficients are:
- \( a = 4 \)
- \( b = 3 \)
- \( c = -7 \)
Now, substituting these values into the discriminant formula:
\[ D = (3)^2 - 4(4)(-7) \] \[ D = 9 - 4(4)(-7) \] \[ D = 9 - 4(-28) \] \[ D = 9 + 112 \] \[ D = 121 \]
Since the discriminant \( D = 121 \) is positive, this indicates that the quadratic equation has two real solutions.
Therefore, the correct statement is: There will be two real solutions since the discriminant is positive.