To determine the number of real solutions for the quadratic equation \(4x^2 + 3x - 7 = 0\), we first need to calculate the discriminant. The discriminant \(D\) is given by the formula:
\[ D = b^2 - 4ac \]
where \(a\), \(b\), and \(c\) are the coefficients from the quadratic equation \(ax^2 + bx + c = 0\).
In this case:
- \(a = 4\)
- \(b = 3\)
- \(c = -7\)
Now, plug these values into the discriminant formula:
\[ D = (3)^2 - 4(4)(-7) \] \[ D = 9 - 4 \cdot 4 \cdot -7 \] \[ D = 9 - (-112) \] \[ D = 9 + 112 \] \[ D = 121 \]
Since the discriminant \(D = 121\) is positive, it indicates that there are two distinct real solutions.
Therefore, the correct statement is:
There will be two real solutions since the discriminant is positive.