When you jump out of the plane, you have mg down and noting up so you accelerate down at g. a = -g/m, v = -g t , h = Hi - (1/2) g t^2
When you deploy the parachute it exerts a drag force up on you approximately proportional to v^2
ma = -mg + k v^2
when the drag becomes equal to the weight
in other words k v^2 = mg
the acceleration, a , becomes zero and you proceed at constant velocity down
Use the concepts of force, acceleration, and speed to explain how a parachute works.
Make sure your answer explains how Newton’s laws of motion play a part.
2 answers
typo
a = -g
a = -g