Use technology to find points and then graph the function y, equals, left parenthesis, one half, right parenthesis, start superscript, x, minus, 1, end superscript, minus, 10, commay=(

2
1

)
x−1
−10, following the instructions below.
Equation of asymptote:
y, equalsy=

Plot at least five points with integer coordinates that fit on the axes below.

1 answer

To analyze the function \( y = \left(\frac{1}{2}\right)^{x-1} - 10 \), we can start with identifying the asymptote and plotting points to graph the function.

Step 1: Identify the Asymptote

The function \( y = \left(\frac{1}{2}\right)^{x-1} - 10 \) approaches the horizontal line \( y = -10 \) as \( x \) increases, since the term \( \left(\frac{1}{2}\right)^{x-1} \) tends to zero.

Equation of the asymptote: \[ y = -10 \]

Step 2: Calculate Points

We will calculate at least five points where \( x \) is an integer.

  1. For \( x = 0 \): \[ y = \left(\frac{1}{2}\right)^{0-1} - 10 = \left(\frac{1}{2}\right)^{-1} - 10 = 2 - 10 = -8 \]

  2. For \( x = 1 \): \[ y = \left(\frac{1}{2}\right)^{1-1} - 10 = \left(\frac{1}{2}\right)^{0} - 10 = 1 - 10 = -9 \]

  3. For \( x = 2 \): \[ y = \left(\frac{1}{2}\right)^{2-1} - 10 = \left(\frac{1}{2}\right)^{1} - 10 = \frac{1}{2} - 10 = -9.5 \]

  4. For \( x = 3 \): \[ y = \left(\frac{1}{2}\right)^{3-1} - 10 = \left(\frac{1}{2}\right)^{2} - 10 = \frac{1}{4} - 10 = -9.75 \]

  5. For \( x = 4 \): \[ y = \left(\frac{1}{2}\right)^{4-1} - 10 = \left(\frac{1}{2}\right)^{3} - 10 = \frac{1}{8} - 10 = -9.875 \]

Points

Here are the points we've calculated:

  • \( (0, -8) \)
  • \( (1, -9) \)
  • \( (2, -9.5) \)
  • \( (3, -9.75) \)
  • \( (4, -9.875) \)

Summary of Points

We have five calculated points:

  1. \( (0, -8) \)
  2. \( (1, -9) \)
  3. \( (2, -9.5) \)
  4. \( (3, -9.75) \)
  5. \( (4, -9.875) \)

Graphing

To plot these points:

  • Draw the horizontal asymptote at \( y = -10 \).
  • Mark the calculated points on the graph, noting that as \( x \) increases, \( y \) approaches closer to -10 but never actually reaches it.

This will give us a clear view of the behavior of the function.