3x+4(x-2)=27
3x+4x-8=27
7x-8=27
7x=35
x=5
Use substitution to solve the linear system.
3x+4y=27
y=x-2
8 answers
y=3
thx
Same as first one except choices i got B is this correct. If not what is it and how do you get this answer?
3x+4y=-11
y=-x-2
A. (-5,1) B.(4,-6) C. (3,-5)
D. No Solution
Same as first one except choices i got B is this correct. If not what is it and how do you get this answer?
3x+4y=-11
y=-x-2
A. (-5,1) B.(4,-6) C. (3,-5)
D. No Solution
the answer is C
3x+4(-x-2)=-11
3x-4x-8=-11
-1x-8=-11
-1x=-3
x=3
y= -(3)-2
y=-5
any questions?
3x+4(-x-2)=-11
3x-4x-8=-11
-1x-8=-11
-1x=-3
x=3
y= -(3)-2
y=-5
any questions?
Ahhh i miss coulculated.
one more i thank im geting the hang of it now tho.
y=x-2
y=2x
one more i thank im geting the hang of it now tho.
y=x-2
y=2x
set it up like this
x-2=2x
then x=-2
x-2=2x
then x=-2
does y=0
No , y is not zero. It is twice x