Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

Question

Responses

a) 1.68

b) 0.75

c) 0.59

d) 1.95

Answer 1

We know that Snell's law is given by:

n1sinθ1 = n2sinθ2

where n1 is the index of refraction of the first medium (air), θ1 is the incident angle, n2 is the index of refraction of the second medium (glass), and θ2 is the angle of refraction.

We can use this equation to find n2:

n2 = n1sinθ1/sinθ2

Substituting the given values:

n2 = 1.00(sin60)/sin31

n2 = 1.68

Therefore, the index of refraction of the glass is 1.68.

Answer: (a) 1.68

Answer 2

1.It is upside down and smaller than the object.
2.They bounce back.
3.Magnified
4.They bend.
5.1.68
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Answer 3

100% is correct