To solve for the index of refraction of the glass, we can use Snell's law which is given as:
n1 * sin(theta1) = n2 * sin(theta2)
Where:
n1 = index of refraction of the medium the light ray is traveling in (air) = 1.00
theta1 = incident angle = 60 degrees
n2 = index of refraction of the glass (what we want to find)
theta2 = angle of refraction = 31 degrees
Plugging in the values:
1.00 * sin(60) = n2 * sin(31)
1.00 * 0.866 = n2 * 0.515
n2 = 0.866 / 0.515
n2 = 1.68
Therefore, the index of refraction of the glass is 1.68.
So, the correct response is 1.68.
Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)
Responses
1.68
0.59
1.95
0.75
1 answer