Use Snell’s law to determine the index of refraction of a sample of glass if a light ray that strikes the glass from air at an incident angle of 60 degrees bends to an angle of 31 degrees from the normal in the glass. (Note: Use 1.00 as the index of refraction for air.)(1 point)

Responses

1.68

0.59

1.95

0.75

1 answer

To solve for the index of refraction of the glass, we can use Snell's law which is given as:

n1 * sin(theta1) = n2 * sin(theta2)

Where:
n1 = index of refraction of the medium the light ray is traveling in (air) = 1.00
theta1 = incident angle = 60 degrees
n2 = index of refraction of the glass (what we want to find)
theta2 = angle of refraction = 31 degrees

Plugging in the values:

1.00 * sin(60) = n2 * sin(31)
1.00 * 0.866 = n2 * 0.515
n2 = 0.866 / 0.515
n2 = 1.68

Therefore, the index of refraction of the glass is 1.68.
So, the correct response is 1.68.