Use point-slope form to write the equation of a line that passes through the point (2,8) with slope -1/3

1 answer

The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) represents a point on the line and m represents the slope of the line.

In this case, the point is (2,8) and the slope is -1/3. Plugging these values into the point-slope form, we get:

y - 8 = -1/3(x - 2)

Simplifying further,

y - 8 = -1/3x + 2/3

Finally, we can rearrange the equation to obtain the slope-intercept form:

y = -1/3x + 2/3 + 8

Simplifying further,

y = -1/3x + 26/3

Therefore, the equation of the line that passes through the point (2,8) with a slope of -1/3 is y = -1/3x + 26/3.