The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) represents a point on the line and m represents the slope of the line.
In this case, the point is (2,8) and the slope is -1/3. Plugging these values into the point-slope form, we get:
y - 8 = -1/3(x - 2)
Simplifying further,
y - 8 = -1/3x + 2/3
Finally, we can rearrange the equation to obtain the slope-intercept form:
y = -1/3x + 2/3 + 8
Simplifying further,
y = -1/3x + 26/3
Therefore, the equation of the line that passes through the point (2,8) with a slope of -1/3 is y = -1/3x + 26/3.
Use point-slope form to write the equation of a line that passes through the point (2,8) with slope -1/3
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