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Use L'Hospital's Rule to solve:

lim u --> 1 of (u-1)^3/ ((1/u) - u^2 + (3/u) - 3)

Ok, so what I thought was that it is type 0/0
so taking the derivatives of the top and bottom

3(u-1)^2 /(-u^-2 -2u - 3u^-3)
and subbing in u = 1
= 0/-6
= 0

2 answers

Looks good to me

Ok. Thanks. The answer key said -1 though. So I thought I might have done something wrong.

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