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Use l'hopital's Rule to evaluate lim x in 0 of

(4x(cos 6x-1 )) / sin 3x-3x

1 answer

That would be

4(cos(6x-1) - 6xsin(6x-1))
------------------------------
3cos(3x) - 3

at x=0 that is

4(cos(-1)-0)
----------------
3-3

-> -∞
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