use integer values of x from -3 to graph the equation.

Question

(the x has a 2 above it,like to the second power) y=-2x+3

I don't know how to do this kind of math.

Answer 1

If y = -2x^2 + 3, then just use the values of x and calculate the values of y:

x y
-3 -2(9)+3 = -15
-2 -2(4)+3 = -5
-1 -2(1)+3 = 1
0 -2(0)+3 = 3
1 1
2 -5
3 -15

Plot those points and sketch a smooth curve through them.

Your graph should look like the one given by wolframalpha:

http://www.wolframalpha.com/input/?i=-2x^2%2B3

Answer 2

The Y axis on the graph 6,5,4,3,2,1,0,-1,-2,-3,-4,-5,-6 and that's the end of that axis.
The X axis on the graph
-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and that's the end of that axis. So I don't know where to graph those points.