the line through (3,1) and (1,8) is 7x+2y = 23
the line through (0,0) and (1,8) is y = 8x
the line through (0,0) and (3,1) is y = 1/3 x
So, the area is
∫[0,1] (23-7x)/2-x/3 dx + ∫[1,3] 8x-x/3 dx
no sweat, eh?
See the lines at
http://www.wolframalpha.com/input/?i=plot+7x%2B2y%3D23%2Cy%3D8x%2Cy%3D1%2F3+x+for+x+%3D+-2..4
Use calculus to find the area A of the triangle with the given vertices.
(0, 0), (3, 1), (1, 8)
A = ????
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