Under root (X2-X1) the whole square +(Y2-Y1) the whole square.
Under root (1-(-7))whole square + (-4-11)whole square.
Under root (1+7)whole square + (-15)whole square.
Under root 8 square + 225
Under root 64 + 225
Under root 289
square root of17 is 289
SO ROOT OF 289 IS 17
ANSWER IS 17.
PLEASE SEND ME THE ANSWERS TO MY EMAIL ADDRESS
Find the midpoint of PQ if P(-7, 11) and Q(1, -4).
Find the area of the rectangle with vertices B(8, 0), T(2, -9), R(-1, -7) and C(5, 2).
Find the area of a triangle with vertices (0, 0), E(3, 1) and F(-2, 6).
Given a rhombus with points E(-4, 1), F(2, 3), G(4, 9) and H(-2, 7), find the slopes of the diagonals.
A line passes through points (-2, -1) and (4, 3). Where does the line intersect the x-axis?
I will be happy to critique your thinking and work on this. I wont do if for you.
Send you the answerx?? Who exactly is getting the education here? :)
Give us some idea where the difficulty is and what you've tried. We'll give advice then. K?
3 answers
1/2Ix1(y2-y3)+x2(y3-y1)+x3(y1-y2)I
1/2I0(1-6)+3(6-0)+(-2)(0-1)I
1/2I0+18-2I
1/2I16I
1/2X16
8 Answer
1/2I0(1-6)+3(6-0)+(-2)(0-1)I
1/2I0+18-2I
1/2I16I
1/2X16
8 Answer
I dont know so why wont you tell us the answer
5 answers