Use bond enthalpy values to calculate the enthalpy change for the following reaction. Then, label if the reaction is endothermic or exothermic

Question

CH4 (g) + Br2 (g) —> CH3Br (g) + HBr (g)
-H
H-C-H O - O O = C = O H - O - H
-H

H - Br

Bond Breaking Bond making
————————————————

Answer 1

————————
C-H (413 kJ/mol) + Br-Br (193 kJ/mol) - C-Br (346 kJ/mol) - H-Br (366 kJ/mol)

Enthalpy change = -(413 + 193) + (346 + 366) = -60 kJ/mol

The reaction is exothermic.