ethene has one C=C bond , and four C-H bonds
(1 * 612) + (4 * 412) = ?
The enthalpy of atomisation is the enthalpy change upon breaking the bonds of 1 mole of a gaseous compound into its atom constituents. Using the table of average bond enthalpies below calculate the enthalpy of atomisation of ethene (C2H4): Bond Average bond enthalpy /kJ mol-1
C=C 612
C-H 412
The enthalpy of atomisation of ethene is:
Can someone help me as this is really confusing me. Thanks in advance
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