The enthalpy of atomisation is the enthalpy change upon breaking the bonds of 1 mole of a gaseous compound into its atom constituents. Using the table of average bond enthalpies below calculate the enthalpy of atomisation of ethene (C2H4): Bond Average bond enthalpy /kJ mol-1

C=C 612
C-H 412
The enthalpy of atomisation of ethene is:

Can someone help me as this is really confusing me. Thanks in advance

1 answer

ethene has one C=C bond , and four C-H bonds

(1 * 612) + (4 * 412) = ?