Use any method to locate the zeros of y=−3x2+12x+15 .(1 point) Responses (1,0)(−5,0) left parenthesis 1 comma 0 right parenthesis left parenthesis negative 5 comma 0 right parenthesis There are no zeros. There are no zeros. (0,15) left parenthesis 0 comma 15 right parenthesis (−1,0)(5,0) left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis

Answer 1

To locate the zeros of the quadratic equation y = -3x^2 + 12x + 15, we can set y equal to zero and solve for x.

0 = -3x^2 + 12x + 15

Dividing the equation by -3 to simplify, we get:

0 = x^2 - 4x - 5

Next, we can factor the equation:

0 = (x - 5)(x + 1)

Setting each factor equal to zero and solving for x, we find the zeros:

x - 5 = 0 ---> x = 5

x + 1 = 0 ---> x = -1

Therefore, the zeros of the equation are (5,0) and (-1,0).

Answer 2

What is 400 - 26 61/18 ?