Question

Use any method to locate the zeros of y=−3x2+12x+15 .(1 point)
Responses

There are no zeros.
There are no zeros.

(−1,0)(5,0)
left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis

(0,15)
left parenthesis 0 comma 15 right parenthesis

(1,0)(−5,0)

Answer 1

Complete the square to identify the vertex of y=x2−16x+14 .(1 point)
Responses

(8,14)
left parenthesis 8 comma 14 right parenthesis

(8,30)
left parenthesis 8 comma 30 right parenthesis

(8,78)
left parenthesis 8 comma 78 right parenthesis

(8,−50)

Answer 2

The zeros of the equation y=−3x^2+12x+15 can be found by setting y equal to zero and solving for x.

Setting y=0, we get:

0 = −3x^2 + 12x + 15

Now, we can try factoring or using the quadratic formula to solve for x.

By factoring:
0 = −3x^2 + 12x + 15
0 = −(x^2 - 4x - 5)
0 = −(x-5)(x+1)

From this, we can see that the zeros are x = 5 and x = -1.

So, the correct answer is:
(−1,0)(5,0)