Use a graphing utility to approximate (to two-decimal-place accuracy) any relative minimum or maximum values of the function.
y=x^3 - 6x^2 + 15
My answer was (4,12) for min and(0,-12) for max.
1 answer
y=x+2
y=x^3 - 6x^2 + 15
My answer was (4,12) for min and(0,-12) for max.
1 answer