Asked by Alice
Use a comparison test to determine if the integral from 8 to infinity of sin^10(x)e^(-x) converges or diverges?
I am stuck on what to use to compare. Any help is appreciated! Thank you!
I was thinking -1<sin<1 but then I get 1<sin^10<1 which makes no sense
I am stuck on what to use to compare. Any help is appreciated! Thank you!
I was thinking -1<sin<1 but then I get 1<sin^10<1 which makes no sense
Answers
Answered by
Steve
since |sinx| <= 1,
0 < sin^10(x) e^-x <= e^-x
since ∫e^-x dx converges so does this one.
0 < sin^10(x) e^-x <= e^-x
since ∫e^-x dx converges so does this one.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.