Assume we start with 1 unit of each
after t = 2 hrs = 120 minutes
amount of 162ho = 1(1/2)^(120/22)
amount of 164ho = 1(1/2)^(120/37)
ratio of the two = 1(1/2)^(120/22) / 1(1/2)^(120/37)
= (1/2)^(120/22 - 120/37)
= (1/2)^(900/407)
= .2159
= .216 to 3 decimals
= 216 : 1000
=27 : 125
Use a calculator to help solve the problem.
One isotope of holmium, 162Ho, has a half life of 22 minutes. The half-life of a second isotope, 164Ho, is 37 minutes. Starting with a sample containing equal amounts, find the ratio of the amounts of 162Ho to 164Ho after two hours. (Round your answer to three decimal places.)
3 answers
amount162/amount164= 100/100 * e^(-.692*60/22)/e^(-.692*60/37)
e^-.692*60(1/22-1/37)=.465
check my work.
e^-.692*60(1/22-1/37)=.465
check my work.
thank you Reiny and Bob