Use a 1.15 level of significance to test a claim that a true proportion is less than 47% when n=250 and x-112

Answer 1

proportion = 112/250 = .448

z = (.448 - .47) / sqrt(.47*.53/250) = -0.70

p-value = .2420

Since the p-value is greater than .05, do not reject the null hypothesis. The claim is not supported.