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A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats a...Question
University football stadium has 81,500 seats. The stadium is a full capacity on game day. Layla believes that only 79,000 seats are occupied find the percent error of Lila’s prediction around your answer to the nearest 100th of a percent
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Answered by
GPT-4o mini
To find the percent error of Layla's prediction, we can use the formula for percent error:
\[
\text{Percent Error} = \left( \frac{|\text{Actual Value} - \text{Predicted Value}|}{\text{Actual Value}} \right) \times 100
\]
In this case:
- Actual Value = 81,500 (the full capacity of the stadium)
- Predicted Value = 79,000 (Layla's belief on occupied seats)
Now, we calculate the absolute error:
\[
|\text{Actual Value} - \text{Predicted Value}| = |81,500 - 79,000| = 2,500
\]
Next, we plug the values into the percent error formula:
\[
\text{Percent Error} = \left( \frac{2,500}{81,500} \right) \times 100
\]
Calculating the fraction:
\[
\frac{2,500}{81,500} \approx 0.0307
\]
Now multiply by 100 to get the percent:
\[
\text{Percent Error} \approx 0.0307 \times 100 \approx 3.07
\]
Finally, rounding to the nearest hundredth of a percent gives us:
\[
\text{Percent Error} \approx 3.07\%
\]
Thus, the percent error of Layla's prediction is approximately **3.07%**.
\[
\text{Percent Error} = \left( \frac{|\text{Actual Value} - \text{Predicted Value}|}{\text{Actual Value}} \right) \times 100
\]
In this case:
- Actual Value = 81,500 (the full capacity of the stadium)
- Predicted Value = 79,000 (Layla's belief on occupied seats)
Now, we calculate the absolute error:
\[
|\text{Actual Value} - \text{Predicted Value}| = |81,500 - 79,000| = 2,500
\]
Next, we plug the values into the percent error formula:
\[
\text{Percent Error} = \left( \frac{2,500}{81,500} \right) \times 100
\]
Calculating the fraction:
\[
\frac{2,500}{81,500} \approx 0.0307
\]
Now multiply by 100 to get the percent:
\[
\text{Percent Error} \approx 0.0307 \times 100 \approx 3.07
\]
Finally, rounding to the nearest hundredth of a percent gives us:
\[
\text{Percent Error} \approx 3.07\%
\]
Thus, the percent error of Layla's prediction is approximately **3.07%**.
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