Question

A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats are occupied. Find the percent error of Layla’s prediction. Round your answer to the nearest hundredth of a percent.(1 point)
Responses

0.0307%
0.0307%

3.07%
3.07%

90.3067%
90.3067%

−3.07% .

Answer 1

To find the percent error of Layla’s prediction, we use the formula for percent error:

\[
\text{Percent Error} = \left( \frac{|\text{Actual Value} - \text{Predicted Value}|}{\text{Actual Value}} \right) \times 100
\]

In this case:
- The actual value (full capacity of the stadium) is 81,500 seats.
- The predicted value (Layla's belief) is 79,000 seats.

Now, we calculate the absolute error:

\[
|\text{Actual Value} - \text{Predicted Value}| = |81,500 - 79,000| = 2,500
\]

Next, we calculate the percent error:

\[
\text{Percent Error} = \left( \frac{2,500}{81,500} \right) \times 100
\]

Calculating this gives:

\[
\text{Percent Error} = \left( 0.0307 \right) \times 100 \approx 3.07\%
\]

Thus, the percent error of Layla’s prediction, rounded to the nearest hundredth of a percent, is:

**3.07%**

So, the correct response is:

**3.07%**