Typically a bullet leaves a standard 45 caliber pistol at 262 m/s. If it takes 1 millisecond to transverse the barrel, determine the average acceleration experienced by the 16.2-gram bullet within the gun's barrel and then compute the average force exerted on it.

1 answer

change in speed = 262 m/s
time = 1 * 10^-3 s
average acceleration = change in speed/change in time = 262 * 10^3 m/s^2
Force = m a = 0.016 Kg * 262 * 10^3 Newtons