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typically a bullet leaves a standard 45 caliber pistol at 262 m/s. if it takes i millisecond to transverse the barrel, determin...Asked by Abakjh
Typically a bullet leaves a standard 45 caliber pistol at 262 m/s. If it takes 1 millisecond to transverse the barrel, determine the average acceleration experienced by the 16.2-gram bullet within the gun's barrel and then compute the average force exerted on it.
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Answered by
Damon
change in speed = 262 m/s
time = 1 * 10^-3 s
average acceleration = change in speed/change in time = 262 * 10^3 m/s^2
Force = m a = 0.016 Kg * 262 * 10^3 Newtons
time = 1 * 10^-3 s
average acceleration = change in speed/change in time = 262 * 10^3 m/s^2
Force = m a = 0.016 Kg * 262 * 10^3 Newtons
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