Two towns T and S are 300km apart, two buses A and B started from town T at the same time moving towards town S, Bus B traveling at speed 10km/h greater than bus A and reached S 1 1/4 hours earlier. Find the average speed of A? How far was Bus A from T when bus B reached Town S?

Answer 1

speed of busA --- x km/h
speed of busB ---(x+10) km/h

time for busA = 300/x
time for busB = 300/(x+10)

300/x - 300/(x+10) = 5/4
times 4x(x+10)

1200(x+10) - 1200x = 5x(x+10)
1200x + 12000 - 1200x = 5x^2 + 50x
5x^2 + 50x - 12000 = 0
x^2 + 10x - 2400 = 0
by formula:
x = 44.24 or some inadmissable negative

speed of bus A = 44.24 km/h
speed of bus B = 54.24 km/h

I assume you can find the second part using the above answers.

Answer 2

Thanks I got it

Answer 3

HOW FAR WAS A FROM T WHEN B RECHED S