v = speed
s = distance
t = time
speed = distance / time
v = s / t
s = v • t
For first bus:
s1 = 64 t
For second bus:
s2 = 60 t
When the buses meet, the total length will be:
s1 + s2 = 186 km
64 t + 60 t = 186
124 t = 186
t = 186 / 124 = 62 • 3 / 62 • 2 =
3 / 2
t = 3 / 2 h = 1.5 h = 1h 30 min
12:00h + 1h 30 min= 13h 30 min =
13:30
A bus leaves town X at 1200 h for town Y at a speed of 64km/h. At the same time another bus leaves town Y for town X travelling at a constant speed of 60 km/h. Given that the distance between the two towns is 186 km,draw a distance _time graph showing both journeys and from your graph find when and where the buses pass each other
1 answer
1 answer