Two teams of nine members each engage in a tug of war. The first team's members have average masses of 64 kg and exert average forces of 1350 N horizontally. The second team's members have average masses of 69 kg and exert average forces of 1365 N horizontally.

Question

Two teams of nine members each engage in a tug of war. The first team's members have average masses of 64 kg and exert average forces of 1350 N horizontally. The second team's members have average masses of 69 kg and exert average forces of 1365 N horizontally.
(a) What is the acceleration of the two teams?(in the direction the heavy team is pulling)

(b) What is the tension in the section of rope between the teams?

Damon · Accepted Answer

net Force = 9(1365-1350) mass = 9(64) + 9(69) so a = 9(1365-1350) /[9(64) + 9(69) ] a = 15/133 = .113 m/s^2 b) T - 9(1350) = 9(64)(.113) T = 12,215