h = Hi + Vi t - 4.9 t^2
up rock
h = 0 + 8.62 t - 4.9 t^2
down rock
h = 5.53 - 8.62 t - 4.9 t^2
so when are the two heights the same?
8.62 t - 4.9 t^2 = 5.53 -8.62 t -4.9 t^2
2(8.62 t) = 5.53
solve for t
then go back and get h
Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is 5.53 m. The stones are thrown with the same speed of 8.62 m/s. Find the location (above the base of the cliff) of the point where the stones cross paths.
I am completely and utterly lost with this problem, and I have no idea where to begin
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