Two sounds have measured intensities of I1 = 110 W/m2 and I2 = 330.00 W/m2. By how many decibels is the level of sound 1 lower than that of sound 2? Answer in dB.

Answer 1

db = 10*Log(I1/I2) = 10*Log(110/330) =
-4.77

I1 = 4.77 db below I2.