Ask a New Question

find the ratio of the intensities of two sounds if one is 8 dB louder than the other

3 answers

10 dB would be a factor of 10 in intensity (power/area).

8 = 10 log_10(I2/I1)
I2/I1 = 10^0.8 = 6.31

20 log (A1/A2) = 2

log(A1/A2) = 0.1

A1/A2 = 10^(0.1) = 1.2589

The ratio of the intensities of the two sound sources is: 𝐼_2/𝐼_1 = 2.

What is the difference in the intensity levels of these sounds?

Ask a New Question or answer this question.

Similar Questions

How does changing the.amplitide of a wave change the type of sound you hear ?Sounds with a bigger amplitude are softer, like a
1. 3 answers
Directions: Read the passage about waves of different wavelengths, frequencies, and amplitudes.A student wonders why some sounds
1. 2 answers
Often when we are watching movies or television, we do not notice all of the sounds that the sound engineer has added. Why not?
1. 1 answer
The intensity of the light from an object varies inversely with the square of the distance. In other words, I = k over d^2a.
1. 1 answer

more similar questions