The kinetic energy (KE) of an object can be calculated using the formula:
\[ KE = \frac{1}{2} mv^2 \]
where \(m\) is the mass and \(v\) is the speed of the object.
For Car A:
- Mass \(m_A = 0.245 , \text{kg}\)
- Speed \(v_A = 10 , \text{cm/s} = 0.1 , \text{m/s}\) (since 1 cm = 0.01 m)
Calculating the kinetic energy for Car A: \[ KE_A = \frac{1}{2} (0.245) (0.1)^2 = \frac{1}{2} (0.245) (0.01) = 0.001225 , \text{J} \]
For Car B:
- Mass \(m_B = 0.245 , \text{kg}\)
- Speed \(v_B = 20 , \text{cm/s} = 0.2 , \text{m/s}\)
Calculating the kinetic energy for Car B: \[ KE_B = \frac{1}{2} (0.245) (0.2)^2 = \frac{1}{2} (0.245) (0.04) = 0.0049 , \text{J} \]
Now, let's compare the kinetic energies:
- \(KE_A = 0.001225 , \text{J}\)
- \(KE_B = 0.0049 , \text{J}\)
Car B has a higher kinetic energy because it has the same mass as Car A but travels at a faster speed. Therefore, the correct answer is:
C. Car B has the higher kinetic energy because of its speed.