To determine which car has the higher kinetic energy, we can use the formula for kinetic energy (KE):
\[ KE = \frac{1}{2} m v^2 \]
where \(m\) is mass and \(v\) is speed.
For Car A:
- Mass (\(m_A\)) = 0.245 kg
- Speed (\(v_A\)) = 10 cm/s = 0.1 m/s (converting to meters for standard units)
\[ KE_A = \frac{1}{2} \times 0.245 , \text{kg} \times (0.1 , \text{m/s})^2 \] \[ KE_A = \frac{1}{2} \times 0.245 \times 0.01 \] \[ KE_A = \frac{1}{2} \times 0.00245 \] \[ KE_A = 0.001225 , \text{J} \]
For Car B:
- Mass (\(m_B\)) = 0.245 kg
- Speed (\(v_B\)) = 20 cm/s = 0.2 m/s
\[ KE_B = \frac{1}{2} \times 0.245 , \text{kg} \times (0.2 , \text{m/s})^2 \] \[ KE_B = \frac{1}{2} \times 0.245 \times 0.04 \] \[ KE_B = \frac{1}{2} \times 0.0098 \] \[ KE_B = 0.0049 , \text{J} \]
Now we compare the kinetic energies:
- \(KE_A = 0.001225 , \text{J}\)
- \(KE_B = 0.0049 , \text{J}\)
Since \(KE_B > KE_A\), we conclude that:
A. Car B has the higher kinetic energy because of its speed.