Equation 1.)
R1+R2=783.4
Equation 2.)
R1*R2/(R1+R2)=Req=783.4
Substitute equation 1 into 2:
R1=783.4-R2
and
R1*R2/(R1+R2)=Req=171.3
(783.4-R2)*R2/783.4-R2+R2=171.3
R2^2-783.4R2=-1.342 x 10^5
R2^2 -783.4R2+1.342 x 10^5=0
(R2 -3.663 x 10^2)^2
R2=3.663 x 10^2 Ω
R1 + R2=783.4 Ω
R1=783.4 Ω-R2
R1=734.4Ω-3.663 x 10^2 Ω
R1=417.1 Ω
Two resistors connected in series have an equivalent resistance of 783.4 Ω. When they are connected in parallel, their equivalent resistance is 171.3 Ω. Find the resistance of each resistor.
Ω (small resistance)
Ω (large resistance
1 answer
1 answer