6 * 6
4 * 9
two rectangles have an area of 36 square inches. Name two possible perimeters for the rectangles.
15 answers
4 & 9
2 & 18
2 & 18
Since area is equal to length * width
Finding the factors of 36 gives the length and width of the possible rectangles
1*36
2*18
3*12
4*9
6*6
Perimeter is equal to
length + length + width + width
so the possible perimeters for the rectangles are
36+36+1+1=74 inches
18+18+2+2=40 inches
12+12+3+3=30 inches
9+9+4+4=26 inches
6+6+6+6=24 inches
Finding the factors of 36 gives the length and width of the possible rectangles
1*36
2*18
3*12
4*9
6*6
Perimeter is equal to
length + length + width + width
so the possible perimeters for the rectangles are
36+36+1+1=74 inches
18+18+2+2=40 inches
12+12+3+3=30 inches
9+9+4+4=26 inches
6+6+6+6=24 inches
FReak you
this is on my homework
2*8. Or 6*9
i don't think that it was right
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1 answer