Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable.

Answer 1

Let's assume that after x minutes, the two vats will have an equal amount of liquid.

The amount of liquid in the first vat after x minutes will be 6x (since it is filling at a rate of 6 gallons per minute).

The amount of liquid in the second vat after x minutes will be 10 + 4x (since it already has 10 gallons and is filling at a rate of 4 gallons per minute).

To find when the two vats will have an equal amount of liquid, we can set the two expressions equal to each other:

6x = 10 + 4x

Simplifying this equation, we get:

2x = 10

x = 5

Therefore, the two vats will have an equal amount of liquid after 5 minutes.

Answer 2

Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable.

Answer 3

Two pumps are filling large vats of liquid. One vat is empty, and the pump is filling it at a rate of 6 gallons per minute. The other is already filled with 10 gallons, and it is continuing to fill at a rate of 4 gallons per minute. Write an equation to show when the two vats will have an equal amount of liquid. Use x as your variable.

Answer 4

Mr bot???

Answer 5

1. 6x = 10 + 4x
2. 8x = 40 + 2x
3. 300 - 15x = 280 + 20x
4. 14
5. 5

Answer 6

number 3 was wrong it was (300−15x=280−20x) it was minus at the 280 and 20x but you had a plus