Two planes approach each other head-on. Each has a speed of 765 km/h, and they spot each other when they are initially 11.0 km apart. How much time do the pilots have to take evasive action?

Answer 1

Since they are traveling at the same speed, each plane has the same amount of time and distance to take evasive action.

d = Vt,
t = d / V = (11/2) / 765 = 0.0072s.

Answer 2

x=x0 + v0t +0.5at^2
Acceleration is zero in the x direction

My numbers are 800km/hr and 10.5 km
Divide the distance between the planes by two since traveling at same speed
0= 5.2 + 800t
Solve for t
t=23.4 seconds

Answer 3

Two planes approach each other head-on. Each has a speed of 760 km/h
k
m
/
h
, and they spot each other when they are initially 12.3 km
k
m
apart.