T = large time , t = small time
t - 3 = T
in 2 hr they each fill some fraction of the pool ... (2 / t) + (2 / T) = 1
(2 / t) + [2 / (t - 3)] = 1 ... 2(t - 3) + 2 t = t(t - 3) ... 4t - 6 = t^2 - 3t
t^2 - 7t + 6 = 0 ... solve for t
Two pipes can be used to fill a pool. Working together, the two pipes can fill the pool in 2 hours. The larger pipe can fill the pool in 3 hours less time than the smaller pipe can alone. Find the time to the nearest tenth of an hour it takes for the smaller pipe working alone to fill the pool. Please help ASAP!!! :(
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