Two pellets, each with a charge of 1.0 microcoulomb (1.0×10−6 ), are located 4.0 (4.0×10−2 ) apart.A)find the electric force between them B)What would be the mass of an object that would experience this same force in Earth's gravitational field?
2 answers
5.6 N
F = k q^2/r^2
= 9x10^9*1x10^-12/16x10^-4
= 5.6 N
5.6=m*9.8 => m=5.6/9.8=5.7 Kg
= 9x10^9*1x10^-12/16x10^-4
= 5.6 N
5.6=m*9.8 => m=5.6/9.8=5.7 Kg
2 answers