Two particles are moving in straight lines. The displacement (meters) of particle 1 is given by the function s(t)= cos(4x), where t is in seconds. The displacement (meters) of particle 2 is given by the function s(t)= t^3/3-t^2/2 +2(t) , where t is in seconds. Find the first positive time at which the particles have the same velocity.

Question

Two particles are moving in straight lines. The displacement (meters) of particle 1 is given by the function s(t)= cos(4x), where t is in seconds. The displacement (meters) of particle 2 is given by the function s(t)= t^3/3-t^2/2 +2(t) , where t is in seconds. Find the first positive time at which the particles have the same velocity. 
(Points : 1)

Steve · Answer

you want where s' is the same for both particles -4sin(4x) = x^2-x+2 Better use a graphing utility of numeric method. See http://www.wolframalpha.com/input/?i=-4sin%284x%29+%3D+x^2-x%2B2

Mary · Answer

Thanks :)