To determine the total momentum after the collision of the two objects in a closed system, we first need to calculate the total momentum before the collision.
Each object has a mass of 1.00 kg and is moving toward each other with a speed of 1.80 m/s. Let's assign one object a positive momentum and the other a negative momentum due to their opposite directions.
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Momentum of the first object (moving in one direction): \[ p_1 = m_1 \times v_1 = 1.00 , \text{kg} \times 1.80 , \text{m/s} = 1.80 , \text{kg·m/s} \]
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Momentum of the second object (moving in the opposite direction): \[ p_2 = m_2 \times v_2 = 1.00 , \text{kg} \times (-1.80 , \text{m/s}) = -1.80 , \text{kg·m/s} \]
Now, we can calculate the total momentum before the collision: \[ \text{Total momentum before collision} = p_1 + p_2 = 1.80 , \text{kg·m/s} + (-1.80 , \text{kg·m/s}) = 0.00 , \text{kg·m/s} \]
In a closed system, the total momentum is conserved during the collision. Therefore, the total momentum after the collision will also be: \[ \text{Total momentum after collision} = 0.00 , \text{kg·m/s} \]
So, the correct answer is: 0.00 kg·m/s