Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Two objects in a closed system collide while moving directly toward each other. Each has a mass of 1.00 kg and is moving at 1.8...Question
Two objects in a closed system collide while moving directly toward each other. Each has a mass of 1.00 kg and is moving at 1.80 m/s. What is the total momentum after the collision?(1 point)
Responses
0.90 kg·m/s
0.90 kg·m/s
1.80 kg·m/s
1.80 kg · m/s
0.00 kg·m/s
0.00 kg·m/s
3.60 kg·m/s
Responses
0.90 kg·m/s
0.90 kg·m/s
1.80 kg·m/s
1.80 kg · m/s
0.00 kg·m/s
0.00 kg·m/s
3.60 kg·m/s
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the total momentum after the collision of the two objects in a closed system, we first need to calculate the total momentum before the collision.
Each object has a mass of 1.00 kg and is moving toward each other with a speed of 1.80 m/s. Let's assign one object a positive momentum and the other a negative momentum due to their opposite directions.
1. Momentum of the first object (moving in one direction):
\[
p_1 = m_1 \times v_1 = 1.00 \, \text{kg} \times 1.80 \, \text{m/s} = 1.80 \, \text{kg·m/s}
\]
2. Momentum of the second object (moving in the opposite direction):
\[
p_2 = m_2 \times v_2 = 1.00 \, \text{kg} \times (-1.80 \, \text{m/s}) = -1.80 \, \text{kg·m/s}
\]
Now, we can calculate the total momentum before the collision:
\[
\text{Total momentum before collision} = p_1 + p_2 = 1.80 \, \text{kg·m/s} + (-1.80 \, \text{kg·m/s}) = 0.00 \, \text{kg·m/s}
\]
In a closed system, the total momentum is conserved during the collision. Therefore, the total momentum after the collision will also be:
\[
\text{Total momentum after collision} = 0.00 \, \text{kg·m/s}
\]
So, the correct answer is:
**0.00 kg·m/s**
Each object has a mass of 1.00 kg and is moving toward each other with a speed of 1.80 m/s. Let's assign one object a positive momentum and the other a negative momentum due to their opposite directions.
1. Momentum of the first object (moving in one direction):
\[
p_1 = m_1 \times v_1 = 1.00 \, \text{kg} \times 1.80 \, \text{m/s} = 1.80 \, \text{kg·m/s}
\]
2. Momentum of the second object (moving in the opposite direction):
\[
p_2 = m_2 \times v_2 = 1.00 \, \text{kg} \times (-1.80 \, \text{m/s}) = -1.80 \, \text{kg·m/s}
\]
Now, we can calculate the total momentum before the collision:
\[
\text{Total momentum before collision} = p_1 + p_2 = 1.80 \, \text{kg·m/s} + (-1.80 \, \text{kg·m/s}) = 0.00 \, \text{kg·m/s}
\]
In a closed system, the total momentum is conserved during the collision. Therefore, the total momentum after the collision will also be:
\[
\text{Total momentum after collision} = 0.00 \, \text{kg·m/s}
\]
So, the correct answer is:
**0.00 kg·m/s**
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.