Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this four-second interval, cycle A has an average acceleration of 1.8 m/s2 due east, while cycle B has an average acceleration of 3.8 m/s2 due east. By how much did the speeds differ at the beginning of the four-second interval?

Question

Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this four-second interval, cycle A has an average acceleration of 1.8 m/s2 due east, while cycle B has an average acceleration of 3.8 m/s2 due east. By how much did the speeds differ at the beginning of the four-second interval?
Which motorcycle was moving faster?

Steve · Answer

If cycle A had velocity a, and cycle B had velocity b, a + 1.8*4 = b + 3.8*4 a-b = 8 a was going 8m/s faster than b makes sense, since b accelerated faster, yet wound up with same speed.

dasdf · Answer

-7.36