Asked by Neil
Two carts of identical mass (500 kg). One is traveling south and the other is traveling east. They collide (inelastic collision) and slide 3 meters, 30 degrees south of the east. The total friction force is 10,000N. Calculate the initial velocities of each.
Answers
Answered by
Elena
The law of conservation of linear momentum for the inelastic collision
x: m1•v1=(m1+m2) •v• cos30°
y: m2•v2=(m1+m2) •v• sin30°
v1=2•v• cos30°
v2=2•v• sin30°
(m1+m2) •a=F(fr)
a= F(fr)/(m1+m2)=F(fr)/2m=10000/2•500=10m/s²
s=v²/2a =>
v=sqrt(2•a•s)=sqrt (2•10•3)=7.75 m/s.
v1=2•v• cos30°=2•7.75 •cos30°=13.42 m/s
v2= 2•v• sin30°=2•7.75 •sin30°=7.75 m/s
x: m1•v1=(m1+m2) •v• cos30°
y: m2•v2=(m1+m2) •v• sin30°
v1=2•v• cos30°
v2=2•v• sin30°
(m1+m2) •a=F(fr)
a= F(fr)/(m1+m2)=F(fr)/2m=10000/2•500=10m/s²
s=v²/2a =>
v=sqrt(2•a•s)=sqrt (2•10•3)=7.75 m/s.
v1=2•v• cos30°=2•7.75 •cos30°=13.42 m/s
v2= 2•v• sin30°=2•7.75 •sin30°=7.75 m/s
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