you have the data to make a sketch. Now, you have two sides, and the included angle. Now connect q and P, and you have a triangle.
a) use law of cosines to solve.
b) I would use law of sines to solve.
Two men P and Q set up from a base town R prospecting for oil. P moves 20km on a bearing 205 degree and Q moves 15km on a bearing 060 degree .calculate
(1) distance of q from P
(2) the bearing of Q from P
2 answers
1. d = 20km[205o] - 15km[60o].
X = 20*sin205 - 15*sin60 = -21.44 km.
Y = 20*Cos205 - 15*Cos60 = -25.63 km.
d = sqrt(X^2 + Y^2) =
2. TanA = X/Y, A = 39.9o W. of S. = 219.9o CW or bearing.
X = 20*sin205 - 15*sin60 = -21.44 km.
Y = 20*Cos205 - 15*Cos60 = -25.63 km.
d = sqrt(X^2 + Y^2) =
2. TanA = X/Y, A = 39.9o W. of S. = 219.9o CW or bearing.
1 answer