DRAW IT !!!!
step 1
head 32 deg E of N 42 km
North distance = 42 cos 32 =35.6
East distance = 42 sin 32 = 22.3
step 2
then head 180 - 154 = 26 deg East of South 28 km
North distance = - 28 cos 26 = - 25.2
East distance = 28 sin 26 = 12.3
Total North = 35.6 - 25.2 = 10.4
Total East = 34.6
tan angle East of North = 34.6 /10.4 = 3.33
Angle East of N = 73.3 degrees
distance = sqrt (10.4*2 + 34.6^2)
a man prospecting oil in the desert leaves his base camp and drives 42km on a bearing of 032degrees. he then drives 28km on a bearing of 154degrees. how far is he then from his base camp and what is his bearing from it
1 answer