Let's assume that it takes x minutes for the two machines to fill the same number of cans of soup.
The first machine fills cans at a rate of 15 per minute, so in x minutes it will fill 15x cans of soup.
The second machine fills cans at a rate of 12 per minute, so in x minutes it will fill 12x cans of soup.
To find when the two machines will have filled the same number of cans of soup, we can set the two expressions equal to each other:
15x = 12x + 30
Simplifying the equation, we get:
3x = 30
Dividing both sides by 3, we get:
x = 10
Therefore, it will take 10 minutes for the two machines to fill the same number of cans of soup.
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable
4 answers
Haven't you beaten this type of problem to death yet? Surely by now you know how to solve them.
Some people dont focus in class.
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable
1 answer